DIVISIORS OF NATURAL NUMBER
STANDARD FORM OF NUMBER:
A number N >1 is said to be expressed in the
standard form N = pa. qb .rc………
Where p, q, r… are distinct primes and a, b, c… are
positive integers.
EXAMPLE:
Standard form of 36 = 22 x 32
Standard form of 120 = 23 x 31 x
51
The number of divisors of a natural
number
The number of divisors
of a natural number N is denoted by d (N).
Steps for finding the
number of divisors of a natural number.
Step 1: Write the given
natural number in standard form i.e. N = pa. qb
.rc………
Step 2: d (N) = (a+1) (b+1)(c+1)…
EXAMPLE:
1. Find the number of divisors of 36.
36 = 22 x 32
d (36) = (2+1)(2+1)
= 3 x 3
= 9.
2. Find the number of divisors of 120.
120 = 23 x 31 x 51
d (120) = (3+1)(1+1)(1+1)
= 4 x 2
x 2
= 16.
The number
of odd divisors of a natural number
Steps for finding the
number odd divisors of a natural number.
Step 1: write the number in standard form.
Step 2: Then, consider only the exponents of odd prime factors.
Step 3: Add 1 to each of these exponents and multiply the results together.
Step 4: The final product is the number of odd divisors.
EXAMPLE:
1. Find the number of odd divisors of 36:
Standard form: 36 = 22 x 32
Consider odd prime factors: 32
Add 1 to each odd exponent: (2 + 1) = 3
No. of odd divisors of 36 = 3
2. Find the number of odd divisors of 120:
Prime Factorization: 120 = 23 x 31 x 51
Consider odd prime factors: 31 and 51
Add 1 to each odd exponent and multiply them: (1 +1) (1+1)
No. of odd divisors of 120 = 2 x
2
= 4.
The number of even divisors
of a natural number.
Number of Even Divisors = Number of Total Divisors – Number of Odd
Divisors
EXAMPLE:
1. Find the number
of even divisors of 36:
Number of total
divisors = 9
Number of odd
divisors = 3
Number of even divisors
= 9-3 =6
FOR MORE UNDERSTANDING
|
NUBER |
DIVISORS |
ODD DIVISORS |
EVEN DIVISORS |
|
36 |
1, 2, 3, 4, 6, 9, 12,18, 36 |
1, 3, 9 |
2, 4, 6, 12, 18, 36 |
|
TOTAL |
9 |
3 |
6 |
.png)
0 Comments